From 6822f76a7aba2727ff365464f865a162df8d9be5 Mon Sep 17 00:00:00 2001
From: Oyetomi Oyelaja <torreyjh@gmail.com>
Date: Thu, 23 Jul 2026 08:38:23 +0200
Subject: [PATCH] Lab Javascript basic algorithms done.

---
 index.js | 44 ++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 44 insertions(+)

diff --git a/index.js b/index.js
index 6b0fec3ad..103e3bc6a 100644
--- a/index.js
+++ b/index.js
@@ -1,7 +1,51 @@
 // Iteration 1: Names and Input
 
+//1.1 Create a variable with the driver's name
+const hacker1 = "Alice";
+
+//1.2 Print the driver's name
+console.log("The driver's name is " + hacker1);
+
+//1.3 Create a variable with the navigator's name
+const hacker2 = "Jack";
+
+//1.4 Print the navigator's name
+console.log("The navigator's name is " + hacker2);
+
+
 
 // Iteration 2: Conditionals
 
 
+//Comparing name length with conditions
+if(hacker1.length > hacker2.length) {
+    console.log(`The driver has the longest name, it has ${hacker1.length} 
+        characters.`);
+    } 
+    else if (hacker2.length > hacker1.length) {
+        console.log (`It seems that the navigator has the longest name, it
+             has ${hacker2.length} characters.` );
+    }
+    else {
+        console.log(`Wow, you both have equally long names, ${hacker1.length} characters!`);
+    }
+
+
 // Iteration 3: Loops
+
+//3.1
+const spacedName = hacker1.toUpperCase().split('').join('');
+console.log(spacedName);
+
+//3.2
+const reversedName = hacker2.split('').reverse().join('');
+console.log(reversedName);
+
+//3.3 lexicological order//
+if (hacker1 < hacker2) {
+    console.log(`The driver's name goes first.`);
+} else if (hacker1 > hacker2) {
+    console.log(`Yo, the navigator goes first, definitely.`);
+} else {
+    console.log(`What?! You both have the same name?`);
+}